For n2n\geq 2, the alternating group AnA_n is the

An=ker(sgn:Sn{1,1}),A_n=\ker\bigl(\operatorname{sgn}:S_n\to\{1,-1\}\bigr),

where SnS_n is the group of under composition and sgn\operatorname{sgn} is the .

Properties

Thus AnA_n consists exactly of the even permutations.

The subgroup AnA_n is in SnS_n and has index 22, hence An=n!/2|A_n|=n!/2. For n5n\geq 5, AnA_n is nonabelian simple.