Existence and uniqueness of splitting fields
Every nonconstant polynomial has a splitting field, unique up to K-isomorphism.
Let be a field and let be a nonconstant polynomial.
Theorem (Splitting fields: existence and uniqueness).
- (Existence) There exists a field extension such that factors in as a product of linear polynomials and is generated by the roots of , i.e. where are all the roots of in . Such an is called a splitting field of over . In particular, is an algebraic extension and is finite.
- (Uniqueness up to -isomorphism) If and are splitting fields of over , then there is a -isomorphism . Equivalently: given a splitting field of , any -embedding of into an algebraic closure of is determined by the images of the roots and must send onto another splitting field of .
Remarks
A common construction of adjoins roots one at a time using simple extensions and then uses the tower law to control degrees.
Examples
- Over , has roots . A splitting field is , and .
- Over , has one real root and two complex roots , , where is a primitive cube root of unity. A splitting field is . (This is also a basic example of a Galois extension once one checks normality and separability.)
- Over , the polynomial has as its roots exactly the elements of . Its splitting field over is , illustrating how finite fields arise as splitting fields.