Existence and uniqueness of splitting fields
Let be a field and let be a nonconstant polynomial.
Theorem (Splitting fields: existence and uniqueness).
(Existence) There exists a field extension such that factors in as a product of linear polynomials and is generated by the roots of , i.e.
where are all the roots of in . Such an is called a splitting field of over . In particular, is an algebraic extension and is finite.
(Uniqueness up to -isomorphism) If and are splitting fields of over , then there is a -isomorphism . Equivalently: given a splitting field of , any -embedding of into an algebraic closure of is determined by the images of the roots and must send onto another splitting field of .
A common construction of adjoins roots one at a time using simple extensions and then uses the tower law to control degrees.
Examples
Over , has roots .
A splitting field is , and .Over , has one real root and two complex roots , , where is a primitive cube root of unity.
A splitting field is . (This is also a basic example of a Galois extension once one checks normality and separability.)Over , the polynomial has as its roots exactly the elements of .
Its splitting field over is , illustrating how finite fields arise as splitting fields.