Jacobson radical annihilates simple modules

Every element of the Jacobson radical acts as zero on any simple module.
Jacobson radical annihilates simple modules

The Jacobson radical can be defined and studied through its action on modules. One of its basic properties is that it kills every simple module, making it invisible in the semisimple world. In the commutative setting, this is closely tied to .

Theorem

Let RR be a ring (commutative or not), and let J(R)J(R) denote its Jacobson radical. Then for every simple (right) RR-module SS,

J(R)S=0. J(R)\cdot S = 0.

Equivalently,

J(R)AnnR(S) J(R)\subseteq \operatorname{Ann}_R(S)

for every simple module SS, where is the ideal of ring elements acting as 00 on SS.

In particular, if RR is commutative, every simple RR-module is of the form R/mR/\mathfrak m for some maximal ideal m\mathfrak m, and the theorem specializes to the inclusion

J(R)mfor all maximal ideals m, J(R)\subseteq \mathfrak m \quad\text{for all maximal ideals }\mathfrak m,

which is exactly the statement that J(R)J(R) equals the intersection of maximal ideals from .

Examples

  1. Local rings.
    If (R,m)(R,\mathfrak m) is a , then J(R)=mJ(R)=\mathfrak m. The unique simple RR-module is the , and m\mathfrak m acts by 00 on it by definition. Hence J(R)J(R) annihilates the simple module.

  2. The integers.
    In R=ZR=\mathbb Z, J(Z)=0J(\mathbb Z)=0 (see ). The simple Z\mathbb Z-modules are Z/pZ\mathbb Z/p\mathbb Z, and indeed 00 acts as 00 on every module.

  3. Dual numbers.
    Let R=k[ε]/(ε2)R=k[\varepsilon]/(\varepsilon^2). Then J(R)=(εˉ)J(R)=(\bar\varepsilon), and the unique simple module is R/(εˉ)kR/(\bar\varepsilon)\cong k. The element εˉ\bar\varepsilon acts as 00 on kk, so J(R)k=0J(R)\cdot k=0.

This principle is one of the standard bridges between ring structure and module structure; it is also a key input in the Artin–Wedderburn picture of semisimple rings, where the Jacobson radical vanishes.